How do I get consistent values with influxdb non_negative_derivative?

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难免孤独
难免孤独 2021-02-01 07:23

Using grafana with influxdb, I am trying to show the per-second rate of some value that is a counter. If I use the non_negative_derivative(1s) function, the value

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  •  囚心锁ツ
    2021-02-01 07:59

    If you want per second results that don't vary, you'll want to GROUP BY time(1s). This will give you accurate perSecond results.

    Consider the following example:

    Suppose that the value of the counter at each second changes like so

    0s → 1s → 2s → 3s → 4s
    1  → 2  → 5  → 8  → 11
    

    Depending on how we group the sequence above, we'll see different results.

    Consider the case where we group things into 2s buckets.

     0s-2s   →    2s-4s
    (5-1)/2  →  (11-5)/2
       2     →      3
    

    versus the 1s buckets

     0s-1s  →  1s-2s  →  2s-3s  →  3s-4s
    (2-1)/1 → (5-2)/1 → (8-5)/1 → (11-8)/1
       1    →    3    →    3    →    3
    

    Addressing

    So to me, that means that the value at a given point should not change that much when expanding the time view, since the value should be rate of change per unit (1s in my example query above).

    The rate of change per unit is a normalizing factor, independent of the GROUP BY time unit. Interpreting our previous example when we change the derivative interval to 2s may offer some insight.

    The exact equation is

    ∆y/(∆x/tu)
    

    Consider the case where we group things into 1s buckets with a derivative interval of 2s. The result we should see is

     0s-1s    →  1s-2s    →  2s-3s    →  3s-4s
    2*(2-1)/1 → 2*(5-2)/1 → 2*(8-5)/1 → (11-8)/1
       2      →    6      →    6      →    6
    

    This may seem a bit odd, but if you consider what this says it should make sense. When we specify a derivative interval of 2s what we're asking for is what the 2s rate of change is for the 1s GROUP BY bucket.

    If we apply similar reasoning to the case of 2s buckets with a derivative interval of 2s is then

     0s-2s     →    2s-4s
    2*(5-1)/2  →  2*(11-5)/2
       4       →      6
    

    What we're asking for here is what the 2s rate of change is for the 2s GROUP BY bucket and in the first interval the 2s rate of change would be 4 and the second interval the 2s rate of change would be 6.

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