What is faster (x < 0) or (x == -1)?

Question

Variable x is int with possible values: -1, 0, 1, 2, 3. Which expression will be faster (in CPU ticks):

1. (x < 0)
2. (x == -1)
         


        

Answer 1

That depends entirely on the ISA you're compiling for, and the quality of your compiler's optimizer. Don't optimize prematurely: profile first to find your bottlenecks.

That said, in x86, you'll find that both are equally fast in most cases. In both cases, you'll have a comparison (cmp) and a conditional jump (jCC) instructions. However, for (x < 0), there may be some instances where the compiler can elide the cmp instruction, speeding up your code by one whole cycle.

Specifically, if the value x is stored in a register and was recently the result of an arithmetic operation (such as add, or sub, but there are many more possibilities) that sets the sign flag SF in the EFLAGS register, then there's no need for the cmp instruction, and the compiler can emit just a js instruction. There's no simple jCC instruction that jumps when the input was -1.