C++ template specialization without default function

Question

I have the following code that compiles and works well:

template
T GetGlobal(const char *name);

template<>
int GetGlobal(cons         


        

Answer 1

I would suggest not to actually provide an implementation, just a bare declaration of the method.

The other option would be to use a compile-time assert. Boost has a number of such beasts.

namespace mpl = boost::mpl;
BOOST_MPL_ASSERT((mpl::or_< boost::same_type,
                            boost::same_type >));

There is also its message version counterpart, which would help.