How to pass a tuple argument the best way?

Question

How to pass a tuple argument the best way ?

Example:

def foo(...): (Int, Int) = ...

def bar(a: Int, b: Int) = ...

Now I would like to

Answer 1

It is worth also knowing about

foo(...) match { case (a,b) => bar(a,b) }

as an alternative that doesn't require you to explicitly create a temporary fooResult. It's a good compromise when speed and lack of clutter are both important. You can create a function with bar _ and then convert it to take a single tuple argument with .tupled, but this creates a two new function objects each time you call the pair; you could store the result, but that could clutter your code unnecessarily.

For everyday use (i.e. this is not the performance-limiting part of your code), you can just

(bar _).tupled(foo(...))

in line. Sure, you create two extra function objects, but you most likely just created the tuple also, so you don't care that much, right?