Pythonic way to determine whether not null list entries are 'continuous'

Question

I\'m looking for a way to easily determine if all not None items in a list occur in a single continuous slice. I\'ll use integers as examples of not None items

Answer 1

Here's a way just using numpy :

a = np.array([1, 2, 3, np.nan, 4, 5, np.nan, 6, 7])

# This returns indices of nans
# eg. [[3], [6]]
# use .squeeze() to convert to [3, 6]
aa = np.argwhere(a != a).squeeze()

# use a diff on your array , if the nans
# are continuous, the diff will always be 1
# if not, diff will be > 1 , and using any() will return True
any(np.diff(aa) > 1)