Code Golf: Triforce

Answer 1

JavaScript 1.8 - SpiderMonkey - 118 chars

N=readline()
function f(n,c)n>0?(c||' ')+f(n-1,c):''
for(i=0;i

w/ bonus - 151 chars

N=readline()
function f(n,c)n>0?(c||' ')+f(n-1,c):''
function l(i)print(f(i)+f(N-i/6,f(11-(z=i%6*2),'*')+f(z+1)))
for(i=0;i

Usage: js thisfile.js

JavaScript - In Browser - 154 characters

N=prompt()
function f(n,c){return n>0?(c||' ')+f(n-1,c):''}
s='
'
for(i=0;i

The non-obfuscated version (before optimizations by gnarf):

var N = prompt();
var S = ' ';

function fill(c, n) {
    for (ret=''; n--;)
        ret += c;
    return ret;
}

var str = '
';

for (i=0; i

Here's a different algorithm that uses replace() to go from one line to the next of each line of a triangle row:

161 characters

N=readline()
function f(n,c){return n>0?(c||' ')+f(n-1,c):''}l=0
for(i=N;i>0;){r=f(i--,f(11,'*')+' ');for(j=6;j--;){print(f(l++)+r)
r=r.replace(/\*\* /g,'   ')}}