Symfony - generate url with parameter in controller

Question

I want to generate a Url directly in my controller. I want to user a url defined in my routing.yml file that needs a parameter.

I\'ve found that code in the Cookbook (Ro

Answer 1

make sure your controller extends Symfony\Bundle\FrameworkBundle\Controller\Controller;

you should also check app/console debug:router in terminal to see what name symfony has named the route

in my case it used a minus instead of an underscore

i.e blog-show

$uri = $this->generateUrl('blog-show', ['slug' => 'my-blog-post']);