Difference between uint and unsigned int?

Question

Is there any difference between uint and unsigned int? I\'m looking in the site, but all question refers to C# or C++. I\'d like to have an answer conc

Answer 1

I am extending a bit answers by Erik, Teoman Soygul and taskinoor

uint is not a standard.

Hence using your own shorthand like this is discouraged:

typedef unsigned int uint;

If you look for platform specificity instead (e.g. you need to specify the number of bits your int occupy), including stdint.h:

#include 

will expose the following standard categories of integers:

• Integer types having certain exact widths

• Integer types having at least certain specified widths

• Fastest integer types having at least certain specified widths

• Integer types wide enough to hold pointers to objects

• Integer types having greatest width

For instance,

Exact-width integer types

The typedef name int N _t designates a signed integer type with width N, no padding bits, and a two's-complement representation. Thus, int8_t denotes a signed integer type with a width of exactly 8 bits.

The typedef name uint N _t designates an unsigned integer type with width N. Thus, uint24_t denotes an unsigned integer type with a width of exactly 24 bits.

defines

int8_t
int16_t
int32_t
uint8_t
uint16_t
uint32_t