Finding closest number in an array

Question

In an array first we have to find whether a desired number exists in that or not? If not then how will I find nearer number to the given desired number in Java?

Answer 1

   int d = Math.abs(desiredNumber - array[i]);
    if (d < bestDistanceFoundYet) {
      // For the moment, this value is the nearest to the desired number...
      nearest = array[i];
    }

In this way you find the last number closer to desired number because bestDistanceFoundYet is constant and d memorize the last value passign the if (d<...).

If you want found the closer number WITH ANY DISTANCE by the desired number (d is'nt matter), you can memorize the last possibile value. At the if you can test

if(d