Ruby: Get all keys in a hash (including sub keys)

Question

let\'s have this hash:

hash = {\"a\" => 1, \"b\" => {\"c\" => 3}}
hash.get_all_keys 
=> [\"a\", \"b\", \"c\"]

how can i get all key

Answer 1

Please take a look of following code:

hash = {"a" => 1, "b" => {"c" => 3}}
keys = hash.keys + hash.select{|_,value|value.is_a?(Hash)}
       .map{|_,value| value.keys}.flatten
p keys

result:

["a", "b", "c"]

New solution, considering @Bala's comments.

class Hash
  def recursive_keys
    if any?{|_,value| value.is_a?(Hash)}
       keys + select{|_,value|value.is_a?(Hash)}
                    .map{|_,value| value.recursive_keys}.flatten
    else
       keys
    end
  end
end

hash =  {"a" => 1, "b" => {"c" => {"d" => 3}}, "e" => {"f" => 3}}
p hash.recursive_keys

result:

["a", "b", "e", "c", "d", "f"]