I need to submit a task in an async framework I\'m working on, but I need to catch for exceptions, and retry the same task multiple times before \"aborting\".
The code I
maybe it's late but hopes someone might find this useful, I recently solved this problem for retrying rest API call on failure. In my case, I have to retry on 500 HTTP status code, below is my rest client code (we are using WSClient from play framework) you can change it to whatever rest-client as per requirement.
int MAX_RETRY = 3;
CompletableFuture future = new CompletableFuture<>();
private CompletionStage getWS(Object request,String url, int retry, CompletableFuture future) throws JsonProcessingException {
ws.url(url)
.post(Json.parse(mapper.writeValueAsString(request)))
.whenCompleteAsync((wsResponse, exception) -> {
if(wsResponse.getStatus() == 500 && retry < MAX_RETRY) {
try {
getWS(request, retry+1, future);
} catch (IOException e) {
throw new Exception(e);
}
}else {
future.complete(wsResponse);
}
});
return future;
}
This code will return immediately if the status code is 200 or other than 500 whereas if HTTP status is 500 it will retry 3 times.