long story short my lecturer is crap, and was showing us infix to prefix stacks via an overhead projector and his bigass shadow was blocking everything so i missed the importan
The algorithm to go from infix to prefix expressions is:
-reverse input
TOS = top of stack
If next symbol is:
- an operand -> output it
- an operator ->
while TOS is an operator of higher priority -> pop and output TOS
push symbol
- a closing parenthesis -> push it
- an opening parenthesis -> pop and output TOS until TOS is matching
parenthesis, then pop and discard TOS.
-reverse output
So your example goes something like (x PUSH, o POP):
2*3/(2-1)+5*(4-1)
)1-4(*5+)1-2(/3*2
Next
Symbol Stack Output
) x )
1 ) 1
- x )- 1
4 )- 14
( o ) 14-
o 14-
* x * 14-
5 * 14-5
+ o 14-5*
x + 14-5*
) x +) 14-5*
1 +) 14-5*1
- x +)- 14-5*1
2 +)- 14-5*12
( o +) 14-5*12-
o + 14-5*12-
/ x +/ 14-5*12-
3 +/ 14-5*12-3
* x +/* 14-5*12-3
2 +/* 14-5*12-32
o +/ 14-5*12-32*
o + 14-5*12-32*/
o 14-5*12-32*/+
+/*23-21*5-41