The R function rep() replicates each element of a vector:
> rep(c(\"A\",\"B\"), times=2)
[1] \"A\" \"B\" \"A\" \"B\"
This is like the list m
Not sure if there's a built-in available for this, but you can try something like this:
>>> lis = ["A", "B"]
>>> times = (2, 3)
>>> sum(([x]*y for x,y in zip(lis, times)),[])
['A', 'A', 'B', 'B', 'B']
Note that sum()
runs in quadratic time. So, it's not the recommended way.
>>> from itertools import chain, izip, starmap
>>> from operator import mul
>>> list(chain.from_iterable(starmap(mul, izip(lis, times))))
['A', 'A', 'B', 'B', 'B']
Timing comparions:
>>> lis = ["A", "B"] * 1000
>>> times = (2, 3) * 1000
>>> %timeit list(chain.from_iterable(starmap(mul, izip(lis, times))))
1000 loops, best of 3: 713 µs per loop
>>> %timeit sum(([x]*y for x,y in zip(lis, times)),[])
100 loops, best of 3: 15.4 ms per loop