How to print an exception in Python 3?

Question

Right now, I catch the exception in the except Exception: clause, and do print(exception). The result provides no information since it always prints

Answer 1

I've use this :

except (socket.timeout, KeyboardInterrupt) as e:
    logging.debug("Exception : {}".format(str(e.__str__).split(" ")[3]))
    break

Let me know if it does not work for you !!