How to print an exception in Python 3?

Question

Right now, I catch the exception in the except Exception: clause, and do print(exception). The result provides no information since it always prints

Answer 1

Here is the way I like that prints out all of the error stack.

import logging

try:
    1 / 0
except Exception as _e:
    # any one of the follows:
    # print(logging.traceback.format_exc())
    logging.error(logging.traceback.format_exc())

The output looks as the follows:

ERROR:root:Traceback (most recent call last):
  File "/PATH-TO-YOUR/filename.py", line 4, in 
    1 / 0
ZeroDivisionError: division by zero

LOGGING_FORMAT :

LOGGING_FORMAT = '%(asctime)s\n  File "%(pathname)s", line %(lineno)d\n  %(levelname)s [%(message)s]'