How to print an exception in Python 3?

Question

Right now, I catch the exception in the except Exception: clause, and do print(exception). The result provides no information since it always prints

Answer 1

Try

try:
    print undefined_var
except Exception as e:
    print(e)

this will print the representation given by e.__str__():

"name 'undefined_var' is not defined"

you can also use:

print(repr(e))

which will include the Exception class name:

"NameError("name 'undefined_var' is not defined",)"