Extending std::list

Question

I need to use lists for my program and needed to decide if I use std::vector or std::list. The problem with vector is that there is no remove method and with list that there is

Answer 1

Given your original problem statement,

I need to use lists for my program and needed to decide if I use std::vector or std::list. The problem with vector is that there is no remove method and with list that there is no operator [].

there is no need to create your own list class (this is not a wise design choice anyway, because std::list does not have a virtual destructor, which is a strong indication that it is not intended to be used as a base class).

You can still achieve what you want using std::vector and the std::remove function. If v is a std::vector, then to remove the value value, you can simply write:

#include 
#include 
T value = ...; // whatever
v.erase(std::remove(v.begin(), v.end(), value), v.end());