Render 'like' button after ajax call

Question

there were a few question similar to mine on the stack but none that answered my question, so...

An ajax call returns the standard html code for creating the like button

Answer 1

Not sure anyone needs it, but my complete code looks like this now and renders both FB page and Like button appropriatelly (LikeLink button created with material icon):



var fbloaded = false; // if SDK is loaded, no need to do it again (though cache should do this?
var fbpageid = "myPageId"; // FB page id

// ajax call to FB SDK script
if (!fbloaded) {
    $.ajax({
        type: "GET",
        url: "//connect.facebook.net/en_US/sdk.js",
        dataType: "script",
        cache: true,
        success: function () {
            fbloaded = true;
            FB.init({
                appId: '{myAppId}',
                version: 'v2.3' // or v2.0, v2.1, v2.0
            });
// parse button after success
            FB.XFBML.parse();
        }
    });
}

var FBDivAppended = false; // if already done, do not call and render again
PostUrl = window.location.href; // like button needs this... or not :)

// when LikeLink is clicked, add the divs needed and at the end fire the FB script ajax call (resetFB)

$("#LikeLink").click(function () {
if (!FBDivAppended) {
            var $pagediv = $("
");
            var $fblikediv = $("
");
            var $fbdiv = $("
");
            var $fbroot = $("
");
            $fbdiv.append($pagediv).append($fblikediv);
            $(".Header").append($fbdiv).append($fbroot);
            FBDivAppended = true;
        }

resetFB();
}