Determine page table size for virtual memory

Question

Consider a virtual memory system with a 38-bit virtual byte address, 1KB pages and 512 MB of physical memory. What is the total size of the page table for each process on this m

Answer 1

size of the page table= total no of page table entries*size of the page table entry

STEP 1:FINDING THE NO OF ENTRIES IN PAGE TABLE:

no of page table entries=virtual address space/page size

=2^38/2^10=2^28

so there are 2^28 entries in the page table

STEP2:NO OF FRAMES IN PHYSICAL MEMORY:

no of frames in the physical memory=(512*1024*1024)/(1*1024)=524288=2^19

so we need 19 bits and additional 4 bits for valid, protection, dirty and use bits totally 23 bits=2.875 bytes

size of the page table=(2^28)*2.875=771751936B=736MB