How to convert a Seq[A] to a Map[Int, A] using a value of A as the key in the map?

Question

I have a Seq containing objects of a class that looks like this:

class A (val key: Int, ...)

Now I want to convert this Seq<

Answer 1

One more 2.8 variation, for good measure, also efficient:

scala> case class A(key: Int, x: Int)
defined class A

scala> val l = List(A(1, 2), A(1, 3), A(2, 1))
l: List[A] = List(A(1,2), A(1,3), A(2,1))

scala> val m: Map[Int, A] = (l, l).zipped.map(_.key -> _)(collection.breakOut)
m: Map[Int,A] = Map((1,A(1,3)), (2,A(2,1)))

Note that if you have duplicate keys, you'll discard some of them during Map creation! You could use groupBy to create a map where each value is a sequence:

scala> l.groupBy(_.key)
res1: scala.collection.Map[Int,List[A]] = Map((1,List(A(1,2), A(1,3))), (2,List(A(2,1))))