Why write `sizeof(char)` if char is 1 by standard?

Question

I was doing some C coding and after reading some C code I\'ve noticed that there are code snippets like

char *foo = (char *)malloc(sizeof(char) * someDynamicAmo         


        

Answer 1

Think of unicode and multi-byte strings. If char represents single character in a string, it can actually occupy more than one byte, resulting in sizeof() > 1