Why write `sizeof(char)` if char is 1 by standard?

Question

I was doing some C coding and after reading some C code I\'ve noticed that there are code snippets like

char *foo = (char *)malloc(sizeof(char) * someDynamicAmo         


        

Answer 1

The common idiom is

T *p = malloc(N * sizeof *p);

or

T *p;
...
p = malloc(N * sizeof *p);

This way you don't have to worry about the type.