Why write `sizeof(char)` if char is 1 by standard?

Question

I was doing some C coding and after reading some C code I\'ve noticed that there are code snippets like

char *foo = (char *)malloc(sizeof(char) * someDynamicAmo         


        

Answer 1

I do sizeof(char) to make the intentions clear. If anyone ever decides he wants foo to be an int he knows he'll need to do sizeof(int) for it to keep on working.

or omit it and use the number

Plus it's not very good coding practice to use magic numbers.