Why write `sizeof(char)` if char is 1 by standard?

Question

I was doing some C coding and after reading some C code I\'ve noticed that there are code snippets like

char *foo = (char *)malloc(sizeof(char) * someDynamicAmo         


        

Answer 1

The more Cish way would be

char* foo = malloc(someDynamicAmount * sizeof *foo);

referencing the variable and not the type so that the type isn't needed. And without casting the result of malloc (which is C++ish).