Can the default destructor be generated as a virtual destructor automatically?

Question

Can the default destructor be generated as a virtual destructor automatically?

If I define a base class but no default destructor, is there a default virtual destructor

Answer 1

Currently, Uri is right. On the other hand, after you have declared a virtual method in your class, you are paying the price for the existence of the virtual table anyway. In fact, the compiler will warn you if your class has a virtual method, but no virtual destructor. This could become a candidate for automatic generation of the default virtual destructor instead of the pesky warning.