Can the default destructor be generated as a virtual destructor automatically?

Question

Can the default destructor be generated as a virtual destructor automatically?

If I define a base class but no default destructor, is there a default virtual destructor

Answer 1

Uri and Michael are right -- I'll just add that if what's bugging you is having to touch two files to declare and define the destructor, it's perfectly all right to define a minimal one inline in the header:

class MyClass
{
   // define basic destructor right here
   virtual ~MyClass(){}

   // but these functions can be defined in a different file
   void FuncA();
   int FuncB(int etc);
}