Return a regex match in a Bash script, instead of replacing it

Question

I just want to match some text in a Bash script. I\'ve tried using sed but I can\'t seem to make it just output the match instead of replacing it with something.

Answer 1

Well , the Sed with the s/"pattern1"/"pattern2"/g just replaces globally all the pattern1s to pattern 2.

Besides that, sed while by default print the entire line by default . I suggest piping the instruction to a cut command and trying to extract the numbers u want :

If u are lookin only to use sed then use TRE:

sed -n 's/.*\(0-9\)\(0-9\)\(0-9\).*/\1,\2,\3/g'.

I dint try and execute the above command so just make sure the syntax is right. Hope this helped.