Ambiguous when two superclasses have a member function with the same name, but different signatures

Question

struct A {
    void f(int x) {}
};

struct B {
    template void f(T x) {}
};

struct C : public A, public B {};

struct D {
    void f(int x){}
    te         


        

Answer 1

What is probably happening is that the template instantiation is happening separately for class A and B, thus ending in two void f(int) functions.

This does not happen in D since there the compiler knows about the void f(int) function as a specialization and therefore does not specialize T for int.