Ambiguous when two superclasses have a member function with the same name, but different signatures

Question

struct A {
    void f(int x) {}
};

struct B {
    template void f(T x) {}
};

struct C : public A, public B {};

struct D {
    void f(int x){}
    te         


        

Answer 1

I believe the compiler prefers A::f (non-template function) over B::f for no reason.
This seems to be a compiler implementation bug more than a implementation dependent detail.

If you add following line, then compilation goes fine and the correct function B::f<> is selected:

struct C : public A, public B { 
  using A::f; // optional
  using B::f;
};

[Funny part is that until the ::f are not brought into the scope of C, they are treated as alien functions.]