Extract directory path and filename

Question

I have a variable which has the directory path, along with the file name. I want to extract the filename alone from the Unix directory path and store it in a variable.

Answer 1

bash to get file name

fspec="/exp/home1/abc.txt" 
filename="${fspec##*/}"  # get filename
dirname="${fspec%/*}" # get directory/path name

other ways

awk

$ echo $fspec | awk -F"/" '{print $NF}'
abc.txt

sed

$ echo $fspec | sed 's/.*\///'
abc.txt

using IFS

$ IFS="/"
$ set -- $fspec
$ eval echo \${${#@}}
abc.txt