It seems that uint32_t
is much more prevalent than uint_fast32_t
(I realise this is anecdotal evidence). That seems counter-intuitive to me, though.
Why do many people use
uint32_t
rather thanuint32_fast_t
?
Note: Mis-named uint32_fast_t
should be uint_fast32_t
.
uint32_t
has a tighter specification than uint_fast32_t
and so makes for more consistent functionality.
uint32_t
pros:
uint32_t
cons:
uint_fast32_t
pros:
uint_fast32_t
cons:
uint32_fast_t
. Looks like many just don't need and use this type. We didn't even use the right name!uint_fast32_t
is only a 1st order approximation.In the end, what is best depends on the coding goal. Unless coding for very wide portability or some niched performance function, use uint32_t
.
There is another issue when using these types that comes into play: their rank compared to int/unsigned
Presumably uint_fastN_t
could be the rank of unsigned
. This is not specified, but a certain and testable condition.
Thus, uintN_t
is more likely than uint_fastN_t
to be narrower the unsigned
. This means that code that uses uintN_t
math is more likely subject to integer promotions than uint_fastN_t
when concerning portability.
With this concern: portability advantage uint_fastN_t
with select math operations.
Side note about int32_t
rather than int_fast32_t
: On rare machines, INT_FAST32_MIN
may be -2,147,483,647 and not -2,147,483,648. The larger point: (u)intN_t
types are tightly specified and lead to portable code.