Storing and updating lists in Python dictionaries: why does this happen?

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一向
一向 2021-01-30 22:19

I have a list of data that looks like the following:

// timestep,x_position,y_position
0,4,7
0,2,7
0,9,5
0,6,7
1,2,5
1,4,7
1,9,0
1,6,8

... and

4条回答
  •  一整个雨季
    2021-01-30 23:12

    Let's look at

    d[t].append(c)
    

    What is the value of d[t]? Try it.

    d = {}
    t = 0
    d[t]
    

    What do you get? Oh. There's nothing in d that has a key of t.

    Now try this.

    d[t] = []
    d[t]
    

    Ahh. Now there's something in d with a key of t.

    There are several things you can do.

    1. Use example 2.
    2. Use setdefault. d.setdefault(t,[]).append(c).
    3. Use collections.defaultdict. You'd use a defaultdict(list) instead of a simple dictionary, {}.

    Edit 1. Optimization

    Given input lines from a file in the above form: ts, x, y, the grouping process is needless. There's no reason to go from a simple list of ( ts, x, y ) to a more complex list of ( ts, (x,y), (x,y), (x,y), ... ). The original list can be processed exactly as it arrived.

    d= collections.defaultdict(list)
    for ts, x, y in someFileOrListOrQueryOrWhatever:
        d[ts].append( (x,y) )
    

    Edit 2. Answer Question

    "when initialising a dictionary, you need to tell the dictionary what the key-value data structure will look like?"

    I'm not sure what the question means. Since, all dictionaries are key-value structures, the question's not very clear. So, I'll review the three alternatives, which may answer the question.

    Example 2.

    Initialization

    d= {}
    

    Use

    if t not in d:
        d[t] = list()
    d[t].append( c )
    

    Each dictionary value must be initialized to some useful structure. In this case, we check to see if the key is present; when the key is missing, we create the key and assign an empty list.

    Setdefault

    Initialization

    d= {}
    

    Use

    d.setdefault(t,list()).append( c )
    

    In this case, we exploit the setdefault method to either fetch a value associated with a key or create a new value associated with a missing key.

    default dict

    Initialization

    import collections
    d = collections.defaultdict(list)
    

    Use

    d[t].append( c )
    

    The defaultdict uses an initializer function for missing keys. In this case, we provide the list function so that a new, empty list is created for a missing key.

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