Remove the first N items that match a condition in a Python list

Question

If I have a function matchCondition(x), how can I remove the first n items in a Python list that match that condition?

One solution is to itera

Answer 1

Using list comprehensions:

n = 3
data = [1, 10, 2, 9, 3, 8, 4, 7]
count = 0
def counter(x):
    global count
    count += 1
    return x

def condition(x):
    return x < 5

filtered = [counter(x) for x in data if count < n and condition(x)]

This will also stop checking the condition after n elements are found thanks to boolean short-circuiting.