How to get “requests per second” for Apache in Linux?

Question

In Windows for ASP, you can get it perfmon, but...

How to get \"requests per second\" for Apache in Linux?

Answer 1

Here is a short bash script I made up to sample the request rate (based on dicroce's suggestion of using wc -l on the log file).

#!/bin/sh

##############################################################################
# This script will monitor the number of lines in a log file to determine the
# number of requests per second.
#
# Example usage:
# reqs-per-sec -f 15 -i /var/www/http/access.log
#
# Author: Adam Franco
# Date: 2009-12-11
# License: http://www.gnu.org/copyleft/gpl.html GNU General Public License (GPL)
##############################################################################

usage="Usage: `basename $0` -f  -l "

# Set up options
while getopts ":l:f:" options; do
 case $options in
 l ) logFile=$OPTARG;;
 f ) frequency=$OPTARG;;
 \? ) echo -e $usage
  exit 1;;
 * ) echo -e $usage
  exit 1;;

 esac
done

# Test for logFile
if [  ! -n "$logFile" ]
then
 echo -e $usage
 exit 1
fi

# Test for frequency
if [  ! -n "$frequency" ]
then
 frequency=60
fi

# Test that frequency is an integer
if [  $frequency -eq $frequency 2> /dev/null ]
then
 :
else
 echo -e $usage
 exit 3
fi

# Test that frequency is an integer
if [  $frequency -lt 1 ]
then
 echo -e $usage
 exit 3
fi

if [ ! -e "$logFile" ]
then
 echo "$logFile does not exist."
 echo 
 echo -e $usage
 exit 2
fi

lastCount=`wc -l $logFile | sed 's/\([0-9]*\).*/\1/'`
while true
do
 newCount=`wc -l $logFile | sed 's/\([0-9]*\).*/\1/'`
 diff=$(( newCount - lastCount ))
 rate=$(echo "$diff / $frequency" |bc -l)
 echo $rate
 lastCount=$newCount
 sleep $frequency
done