Grabbing n bits from a byte

Question

I\'m having a little trouble grabbing n bits from a byte.

I have an unsigned integer. Let\'s say our number in hex is 0x2A, which is 42 in decimal. In binary it looks li

Answer 1

just get rid of the 8* in your code.

int input = 42;
int high3 = input >> 5;
int low5 = input & (32 - 1); // 32 = 2^5
bool isBit3On = input & 4; // 4 = 2^(3-1)