Extract filename and path from URL in bash script

Question

In my bash script I need to extract just the path from the given URL. For example, from the variable containing string:

http://login:password@example.com/one/more/dir/fi

Answer 1

How does this :?

echo 'http://login:password@example.com/one/more/dir/file.exe?a=sth&b=sth' | \
sed 's|.*://[^/]*/\([^?]*\)?.*|/\1|g'

• .://[^/]/: http://login:password@example.com/
• ([^?]*) : one/more/dir/file.exe
• ?.* : ?a=sth&b=sth
• /\1 : /one/more/dir/file.exe