How to upload a file to S3 without creating a temporary local file

Question

Is there any feasible way to upload a file which is generated dynamically to amazon s3 directly without first create a local file and then upload to the s3 server? I use python.

Answer 1

def upload_to_s3(url, **kwargs):
    '''
    :param url: url of image which have to upload or resize to upload
    :return: url of image stored on aws s3 bucket
    '''

    r = requests.get(url)
    if r.status_code == 200:
        # credentials stored in settings AWS_ACCESS_KEY_ID and AWS_SECRET_ACCESS_KEY
        conn = boto.connect_s3(AWS_ACCESS_KEY_ID, AWS_SECRET_ACCESS_KEY, host=AWS_HOST)

        # Connect to bucket and create key
        b = conn.get_bucket(AWS_Bucket_Name)
        k = b.new_key("{folder_name}/{filename}".format(**kwargs))

        k.set_contents_from_string(r.content, replace=True,
                                   headers={'Content-Type': 'application/%s' % (FILE_FORMAT)},
                                   policy='authenticated-read',
                                   reduced_redundancy=True)

        # TODO Change AWS_EXPIRY
        return k.generate_url(expires_in=AWS_EXPIRY, force_http=True)