How to obtain a list of directories within a directory, like list.files(), but instead “list.dirs()”

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梦如初夏
梦如初夏 2021-01-30 12:14

This may be a very easy question for someone - I am able to use list.files() to obtain a list of files in a given directory, but if I want to get a list of director

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  •  轻奢々
    轻奢々 (楼主)
    2021-01-30 13:01

    What about something like this, give it a try:

    dir('.')[file.info(dir('.',full.names=T))$isdir]
    

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