I come from JavaScript which has first class function support. For example you can:
The related section from the specification: Function types.
All other answers here first declare a new type, which is good (practice) and makes your code easier to read, but know that this is not a requirement.
You can work with function values without declaring a new type for them, as seen in the below example.
Declaring a variable of function type which has 2 parameters of type float64
and has one return value of type float64
looks like this:
// Create a var of the mentioned function type:
var f func(float64, float64) float64
Let's write a function which returns an adder function. This adder function should take 2 parameters of type float64
and should returns the sum of those 2 numbers when called:
func CreateAdder() func(float64, float64) float64 {
return func(x, y float64) float64 {
return x + y
}
}
Let's write a function which has 3 parameters, first 2 being of type float64
, and the 3rd being a function value, a function that takes 2 input parameters of type float64
and produces a value of float64
type. And the function we're writing will call the function value that is passed to it as parameter, and using the first 2 float64
values as arguments for the function value, and returns the result that the passed function value returns:
func Execute(a, b float64, op func(float64, float64) float64) float64 {
return op(a, b)
}
Let's see our previous examples in action:
var adder func(float64, float64) float64 = CreateAdder()
result := Execute(1.5, 2.5, adder)
fmt.Println(result) // Prints 4
Note that of course you can use the Short variable declaration when creating adder
:
adder := CreateAdder() // adder is of type: func(float64, float64) float64
Try these examples on the Go Playground.
Of course if you already have a function declared in a package with the same function type, you can use that too.
For example the math.Mod() has the same function type:
func Mod(x, y float64) float64
So you can pass this value to our Execute()
function:
fmt.Println(Execute(12, 10, math.Mod)) // Prints 2
Prints 2
because 12 mod 10 = 2
. Note that the name of an existing function acts as a function value.
Try it on the Go Playground.
Note:
Note that the parameter names are not part of the type, the type of 2 functions having the same parameter and result types is identical regardless of the names of the parameters. But know that within a list of parameters or results, the names must either all be present or all be absent.
So for example you can also write:
func CreateAdder() func(P float64, Q float64) float64 {
return func(x, y float64) float64 {
return x + y
}
}
Or:
var adder func(x1, x2 float64) float64 = CreateAdder()