phpunit avoid constructor arguments for mock

Question

What is the way to avoid phpunit having to call the constructor for a mock object? Otherwise I would need a mock object as constructor argument, another one for that etc. The ap

Answer 1

PHPUnit is designed to call the constructor on mocked objects; to prevent this you should either:

1. Inject a mock object as a dependency into the object you're having trouble mocking
2. Create a test class that extends the class you're trying to call that doesn't call the parent constructor