phpunit avoid constructor arguments for mock

Question

What is the way to avoid phpunit having to call the constructor for a mock object? Otherwise I would need a mock object as constructor argument, another one for that etc. The ap

Answer 1

This question is a little old, but for new visitors, you can do it using the createMock method (previously called createTestDouble and introduced in v5.4.0).

$mock = $this->createMock($className);

As you can see in the code below extracted from the PHPUnit\Framework\TestCase class (in phpunit/src/framework/TestCase.php), it will basically create a mock object without calling the original constructor.

/** PHPUnit\Framework\TestCase::createMock method */
protected function createMock(string $originalClassName): MockObject
{
    return $this->getMockBuilder($originalClassName)
                ->disableOriginalConstructor()
                ->disableOriginalClone()
                ->disableArgumentCloning()
                ->disallowMockingUnknownTypes()
                ->getMock();
}