console.log to stdout on gulp events

Question

I want to log to stdout (the config environment) when a gulp task is running or has run.

Something like this:

gulp.task(\'scripts\', function () {
  var          


        

Answer 1

(PLEASE NOTE - In December 2017, the gulp-util module was deprecated.)

To build on the answer by Jacob Budin, I recently tried this and found it useful.

var gulp = require("gulp");
var util = require("gulp-util");
var changed = require("gulp-changed");

gulp.task("copyIfChanged", function() {
    var nSrc=0, nDes=0, dest="build/js";
    gulp.src("app/**/*.js")
    .on("data", function() { nSrc+=1;})
    .pipe(changed(dest)) //filter out src files not newer than dest
    .pipe(gulp.dest(dest))
    .on("data", function() { nDes+=1;})
    .on("finish", function() {
        util.log("Results for app/**/*.js");
        util.log("# src files: ", nSrc);
        util.log("# dest files:", nDes);
    });
}