Create a file if it doesn't exist

Question

I\'m trying to open a file, and if the file doesn\'t exist, I need to create it and open it for writing. I have this so far:

#open file for reading
fn = input(\"         


        

Answer 1

Well, first of all, in Python there is no ! operator, that'd be not. But open would not fail silently either - it would throw an exception. And the blocks need to be indented properly - Python uses whitespace to indicate block containment.

Thus we get:

fn = input('Enter file name: ')
try:
    file = open(fn, 'r')
except IOError:
    file = open(fn, 'w')