Does unique_ptr::release() call the destructor?

Question

Is this code correct?

auto v =  make_unique(12);
v.release();     // is this possible?

Is it equivalent to delete of a

Answer 1

it may be a bit tricky for arbitrary types:

  unique_ptr v = get_me_some_foo();  // manages the object
  Foo * raw = v.release();        // pointer to no-longer-managed object
  delete raw;

is almost correct.

  unique_ptr v = get_me_some_foo();  // manages the object
  Foo * ptr = v.release();        // pointer to no-longer-managed object
  v.get_deleter() ( ptr );

this one would be correct in all situation; there may be a custom deleter defined on type Foo, but using the deleter returned by the unique_ptr object is good for all cases.