I read this line in a book:
It is provably impossible to build a compiler that can actually determine whether or not a C++ function will change the val
Imagine such compiler exists. Let's also assume that for convenience it provides a library function that returns 1 if the passed function modifies a given variable and 0 when the function doesn't. Then what should this program print?
int variable = 0;
void f() {
if (modifies_variable(f, variable)) {
/* do nothing */
} else {
/* modify variable */
variable = 1;
}
}
int main(int argc, char **argv) {
if (modifies_variable(f, variable)) {
printf("Modifies variable\n");
} else {
printf("Does not modify variable\n");
}
return 0;
}