SQL Server 2008: How to query all databases sizes?

Question

I have MS SQL 2008 R2, 500 databases. What is the most efficient, easiest and \'modern\' way to query all databases sizes.

The output should have columns:

Answer 1

IF OBJECT_ID('tempdb.dbo.#space') IS NOT NULL
    DROP TABLE #space

CREATE TABLE #space (
      database_id INT PRIMARY KEY
    , data_used_size DECIMAL(18,2)
    , log_used_size DECIMAL(18,2)
)

DECLARE @SQL NVARCHAR(MAX)

SELECT @SQL = STUFF((
    SELECT '
    USE [' + d.name + ']
    INSERT INTO #space (database_id, data_used_size, log_used_size)
    SELECT
          DB_ID()
        , SUM(CASE WHEN [type] = 0 THEN space_used END)
        , SUM(CASE WHEN [type] = 1 THEN space_used END)
    FROM (
        SELECT s.[type], space_used = SUM(FILEPROPERTY(s.name, ''SpaceUsed'') * 8. / 1024)
        FROM sys.database_files s
        GROUP BY s.[type]
    ) t;'
    FROM sys.databases d
    WHERE d.[state] = 0
    FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)'), 1, 2, '')

EXEC sys.sp_executesql @SQL

SELECT
      d.database_id
    , d.name
    , d.state_desc
    , d.recovery_model_desc
    , t.total_size
    , t.data_size
    , s.data_used_size
    , t.log_size
    , s.log_used_size
FROM (
    SELECT
          database_id
        , log_size = CAST(SUM(CASE WHEN [type] = 1 THEN size END) * 8. / 1024 AS DECIMAL(18,2))
        , data_size = CAST(SUM(CASE WHEN [type] = 0 THEN size END) * 8. / 1024 AS DECIMAL(18,2))
        , total_size = CAST(SUM(size) * 8. / 1024 AS DECIMAL(18,2))
    FROM sys.master_files
    GROUP BY database_id
) t
JOIN sys.databases d ON d.database_id = t.database_id
LEFT JOIN #space s ON d.database_id = s.database_id
ORDER BY t.total_size DESC