python regex, date format [closed]

Answer 1

You don't need to use regexp.

import datetime

dt = datetime.datetime.now()
print dt.strftime('%B %d')

The result will be:

June 18

BTW, if you want to sort the list of dates and to show year only of those, which are the 2012's, than try to use split():

line = "March 29, YYYY"
if int(line.split(',')[1]) = 2012
    print line
else
    pass