Can anybody tell me why this is happening in c language

Question

 #include 
 //Compiler version gcc 6.3.0

 int main(void)
 {

     float a=10;
    printf(\"%f\"+1,a);

    return 0;
 }

Output -- d

Answer 1

You should definitely compile with all warnings. I used gcc -Wall -Wextra -Werror -pedantic. It didn't compile with my warnings because there are too many arguments for printf.

When I tested out the code you posted, it printed 'f' and 'A???'. I'm not sure what you're trying to do, but I believe it has to do with how your float is adding with the number to give you an Ascii character.