why parenthesis is unable to change c++ operator precedence in this case?

Question

Here\'s my simple code:

int main()
{
    int x = 5;
    cout << (x++) << endl;

    return 0;
}

the code above prints 5

Answer 1

This is because x++ evaluates the value of x (5 in your case) and will increase its value after that....

what you are looking for is the pre-increment, also ++x