why parenthesis is unable to change c++ operator precedence in this case?

Question

Here\'s my simple code:

int main()
{
    int x = 5;
    cout << (x++) << endl;

    return 0;
}

the code above prints 5

Answer 1

The expression (x++), with or without parentheses, evaluates to the previous value of x, and has the side-effect of increasing x.

If you want to see the effect of the increase then use the obscure

cout << (x++, x) << endl;